(y^2-13y+40)/(y^2-2y+48)

Solution for (y^2-13y+40)/(y^2-2y+48) equation:

D( y )

y^2-(2*y)+48 = 0

y^2-(2*y)+48 = 0

y^2-(2*y)+48 = 0

y^2-2*y+48 = 0

y^2-2*y+48 = 0

DELTA = (-2)^2-(1*4*48)

DELTA = -188

DELTA < 0

y in (-oo:+oo)

(y^2-(13*y)+40)/(y^2-(2*y)+48) = 0

(y^2-13*y+40)/(y^2-2*y+48) = 0

y^2-13*y+40 = 0

y^2-13*y+40 = 0

DELTA = (-13)^2-(1*4*40)

DELTA = 9

DELTA > 0

y = (9^(1/2)+13)/(1*2) or y = (13-9^(1/2))/(1*2)

y = 8 or y = 5

(y-5)*(y-8) = 0

y^2-2*y+48 = 0

y^2-2*y+48 = 0

DELTA = (-2)^2-(1*4*48)

DELTA = -188

DELTA < 0

1 = 0

(y-5)*(y-8) = 0

( y-5 )

y-5 = 0 // + 5

y = 5

( y-8 )

y-8 = 0 // + 8

y = 8

y in { 5, 8 }